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40a^2-335a-225=0
a = 40; b = -335; c = -225;
Δ = b2-4ac
Δ = -3352-4·40·(-225)
Δ = 148225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{148225}=385$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-335)-385}{2*40}=\frac{-50}{80} =-5/8 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-335)+385}{2*40}=\frac{720}{80} =9 $
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